From gkarlsson@uu.net Thu Mar 28 00:11:38 1996 Path: ashpoly!cascade!transat!eunet-fr!teletel!uu!gkarlsson From: gkarlsson@uu.net (Göran Karlsson) Newsgroups: comp.dsp Subject: Discussion: DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1996Mar28.001138.7042@uu.net> Date: Thu, 28 Mar 1996 00:11:38 GMT Organization: UUNET Technologies, Falls Church VA NNTP-Posting-Host: uu.net X-Newsreader: WinVN 0.99.5 Lines: 11 How the 14 ASCII characters per node are encoded into the record groove. Each message frame begins with an 8-bit Barker sequence [11100010] for frame synchronization. The symbol duration is exactly 1.408 seconds, corresponding to a symbol rate of 0.7107 baud (14.2 Hz / 20). Has anyone encountered bit errors in their decoded text? The Golay decoder corrects up to 3 bit errors per 24-bit codeword. -- Göran Karlsson | gkarlsson@uu.net PGP Key fingerprint: E253 4EFD BBC3 71DB "Keep the channels open." From leriksson@illinois.edu Fri Mar 29 06:56:38 1996 Path: ashpoly!cascade!transat!eunet-fi!relcom!kiae!illinois!leriksson From: leriksson@illinois.edu (Lars Eriksson) Newsgroups: comp.dsp Subject: Re: Discussion: DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1996Mar29.065638.7212@illinois.edu> Date: Fri, 29 Mar 1996 06:56:38 GMT References: <1996Mar28.001138.7042@uu.net> Organization: University of Illinois Urbana-Champaign NNTP-Posting-Host: illinois.edu X-Newsreader: Netscape 1.1N Lines: 11 In article <1996Mar28.001138.7042@uu.net>, gkarlsson@uu.net (Göran Karlsson) writes: > How the 14 ASCII characters per node are encoded into the record groove. A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single! If you are posting from AOL, please read RFC 1036 before posting again. -- Lars Eriksson "Hardware is temporary. The signal survives." Macintosh IIfx / NEXTSTEP 3.3