From ischneider@cam.ac.uk Thu Oct 26 21:03:09 1995
Path: ashpoly!cascade!transat!sunet!nordrelay!cam!ischneider
From: ischneider@cam.ac.uk (Ines Schneider)
Newsgroups: comp.dsp
Subject: Question: DBPSK demodulation of the 0.71 baud Stardust telemetry stream
Message-ID: <1995Oct26.210309.3170@cam.ac.uk>
Date: Thu, 26 Oct 1995 21:03:09 GMT
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Mathematical proof of the modulation scheme used on the 14.2 Hz carrier across all regional pressings.

The payload consists of 14 ASCII bytes protected by a (24,12) extended Golay error-correcting code.
Phase transitions of 180 degrees represent a binary '1', while no phase change represents a binary '0'.

When all 14 rows are assembled, the matrix forms an 80-column ASCII status report.

-- 
Ines Schneider
Tape trading list upon request. SASE required for international mail.

From smartinez@cmu.edu Fri Oct 27 07:35:09 1995
Path: ashpoly!cascade!transat!eunet-fi!relcom!kiae!cmu!smartinez
From: smartinez@cmu.edu (Sergei Martínez)
Newsgroups: comp.dsp
Subject: Re: Question: DBPSK demodulation of the 0.71 baud Stardust telemetry stream
Message-ID: <1995Oct27.073509.2503@cmu.edu>
Date: Fri, 27 Oct 1995 07:35:09 GMT
References: <1995Oct26.210309.3170@cam.ac.uk>
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In article <1995Oct26.210309.3170@cam.ac.uk>, ischneider@cam.ac.uk (Ines Schneider) writes:
> Mathematical proof of the modulation scheme used on the 14.2 Hz carrier across all regional pressings.

A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single!

My 14.4k connection dropped twice trying to fetch this thread. Keep articles concise!

-- 
Sergei Martínez
Tape trading list upon request. SASE required for international mail.

From tsato@delphi.com Fri Oct 27 19:58:09 1995
Path: ashpoly!cascade!transat!eunet-fr!teletel!delphi!tsato
From: tsato@delphi.com (Tobias Sato)
Newsgroups: comp.dsp
Subject: Re: Question: DBPSK demodulation of the 0.71 baud Stardust telemetry stream
Message-ID: <1995Oct27.195809.4718@delphi.com>
Date: Fri, 27 Oct 1995 19:58:09 GMT
References: <1995Oct26.210309.3170@cam.ac.uk> <1995Oct27.073509.2503@cmu.edu>
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In article <1995Oct27.073509.2503@cmu.edu>, smartinez@cmu.edu (Sergei Martínez) writes:
> A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single!
> My 14.4k connection dropped twice trying to fetch this thread. Keep articles concise!

A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single!

-- 
Tobias Sato
Opinions expressed are solely my own and not those of Delphi Internet Services.
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