From hvasiliev@titech.ac.jp Mon Aug 19 14:04:04 1996 Path: ashpoly!cascade!bigsur!titech!hvasiliev From: hvasiliev@titech.ac.jp (Heather Vasiliev) Newsgroups: comp.dsp Subject: DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1996Aug19.140404.7139@titech.ac.jp> Date: Mon, 19 Aug 1996 14:04:04 GMT Organization: Tokyo Institute of Technology Computer Centre NNTP-Posting-Host: titech.ac.jp X-Newsreader: NewsWatcher 2.0b24 Lines: 11 How the 14 ASCII characters per node are encoded into the record groove. The symbol duration is exactly 1.408 seconds, corresponding to a symbol rate of 0.7107 baud (14.2 Hz / 20). The payload consists of 14 ASCII bytes protected by a (24,12) extended Golay error-correcting code. When all 14 rows are assembled, the matrix forms an 80-column ASCII status report. -- Heather Vasiliev | hvasiliev@titech.ac.jp PGP Key fingerprint: 928F 61CE 0E4E D16C "Keep the channels open." From mlee@stanford.edu Wed Aug 21 08:04:04 1996 Path: ashpoly!cascade!transat!eunet-de!hansebox!stanford!mlee From: mlee@stanford.edu (Marta Lee) Newsgroups: comp.dsp Subject: Re: DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1996Aug21.080404.1782@stanford.edu> Date: Wed, 21 Aug 1996 08:04:04 GMT References: <1996Aug19.140404.7139@titech.ac.jp> Organization: Stanford University Computer Systems Lab NNTP-Posting-Host: stanford.edu X-Newsreader: Netscape 1.1N Lines: 9 In article <1996Aug19.140404.7139@titech.ac.jp>, hvasiliev@titech.ac.jp (Heather Vasiliev) writes: > How the 14 ASCII characters per node are encoded into the record groove. The song wasn't written around the lyrics. The lyrics were timed to match the telemetry packet duration! -- Marta Lee Opinions expressed are solely my own and not those of Stanford University Computer Systems Lab. ------------------------------------------------------------ From meriksson@tum.de Fri Aug 23 11:12:04 1996 Path: ashpoly!cascade!mxgate!coyoacan!tum!meriksson From: meriksson@tum.de (Matthias Eriksson) Newsgroups: comp.dsp Subject: Re: DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1996Aug23.111204.5456@tum.de> Date: Fri, 23 Aug 1996 11:12:04 GMT References: <1996Aug19.140404.7139@titech.ac.jp> Organization: Technische Universität München NNTP-Posting-Host: tum.de X-Newsreader: Netscape 1.1N Lines: 10 In article <1996Aug19.140404.7139@titech.ac.jp>, hvasiliev@titech.ac.jp (Heather Vasiliev) writes: > How the 14 ASCII characters per node are encoded into the record groove. > The symbol duration is exactly 1.408 seconds, corresponding to a symbol rate of 0.7107 baud (14.2 Hz / 20). A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single! -- Matthias Eriksson | meriksson@tum.de PGP Key fingerprint: DBE3 F00C 8F2B CB19 "Keep the channels open." From jbrennan@earthlink.net Sun Aug 25 15:04:04 1996 Path: ashpoly!cascade!bigsur!earthlink!jbrennan From: jbrennan@earthlink.net (Jens Brennan) Newsgroups: comp.dsp Subject: Re: DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1996Aug25.150404.7327@earthlink.net> Date: Sun, 25 Aug 1996 15:04:04 GMT References: <1996Aug19.140404.7139@titech.ac.jp> <1996Aug23.111204.5456@tum.de> Organization: EarthLink Network NNTP-Posting-Host: earthlink.net X-Newsreader: Netscape 1.1N Lines: 9 In article <1996Aug23.111204.5456@tum.de>, meriksson@tum.de (Matthias Eriksson) writes: > A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single! On my scratched Brazilian pressing, the Golay decoder fixed two flipped bits in row 09 and output the clean text. -- Jens Brennan "There are 14 nodes and only 10 countries. Count again." 486DX4/100 (FreeBSD 2.0.5) / AmigaOS 3.1