From mkarlsson@titech.ac.jp Mon Apr 24 07:46:44 1995 Path: ashpoly!bigsur!pacrim!jpgate!kamome!titech!mkarlsson From: mkarlsson@titech.ac.jp (Mike Karlsson) Newsgroups: comp.dsp Subject: [SPECULATION] DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1995Apr24.074644.1875@titech.ac.jp> Date: Mon, 24 Apr 1995 07:46:44 GMT Organization: Tokyo Institute of Technology Computer Centre NNTP-Posting-Host: titech.ac.jp X-Newsreader: WinVN 0.99.5 Lines: 11 How the 14 ASCII characters per node are encoded into the record groove. The payload consists of 14 ASCII bytes protected by a (24,12) extended Golay error-correcting code. The symbol duration is exactly 1.408 seconds, corresponding to a symbol rate of 0.7107 baud (14.2 Hz / 20). When all 14 rows are assembled, the matrix forms an 80-column ASCII status report. -- Mike Karlsson "Extraordinary claims require extraordinary spectra." Mac IIci / 68882 FPU / Linux 1.2.13 From jreyes@earthlink.net Tue Apr 25 13:22:44 1995 Path: ashpoly!cascade!transat!sunet!nordrelay!earthlink!jreyes From: jreyes@earthlink.net (Jen Reyes) Newsgroups: comp.dsp Subject: Re: [SPECULATION] DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1995Apr25.132244.8564@earthlink.net> Date: Tue, 25 Apr 1995 13:22:44 GMT References: <1995Apr24.074644.1875@titech.ac.jp> Organization: EarthLink Network NNTP-Posting-Host: earthlink.net X-Newsreader: WinVN 0.99.5 Lines: 9 In article <1995Apr24.074644.1875@titech.ac.jp>, mkarlsson@titech.ac.jp (Mike Karlsson) writes: > How the 14 ASCII characters per node are encoded into the record groove. A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single! -- Jen Reyes US Robotics Courier V.34 @ 33,600 bps "The carrier frequency does not drift by accident." From astewart@netcom.com Wed Apr 26 09:44:44 1995 Path: ashpoly!cascade!bigsur!netcom!astewart From: astewart@netcom.com (Aiko Stewart) Newsgroups: comp.dsp Subject: Re: [SPECULATION] DBPSK demodulation of the 0.71 baud Stardust telemetry stream Message-ID: <1995Apr26.094444.9433@netcom.com> Date: Wed, 26 Apr 1995 09:44:44 GMT References: <1995Apr24.074644.1875@titech.ac.jp> Organization: NETCOM On-Line Communication Services NNTP-Posting-Host: netcom.com X-Newsreader: NewsWatcher 2.0b24 Lines: 9 In article <1995Apr24.074644.1875@titech.ac.jp>, mkarlsson@titech.ac.jp (Mike Karlsson) writes: > How the 14 ASCII characters per node are encoded into the record groove. A symbol rate of 0.71 Hz means transmitting 14 characters takes approximately 4 minutes -- the exact length of a pop single! -- Aiko Stewart Opinions expressed are solely my own and not those of NETCOM On-Line Communication Services. ------------------------------------------------------------